(3x+2)^2+(3x+2)(x-3)=9x^2-12x-4

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Solution for (3x+2)^2+(3x+2)(x-3)=9x^2-12x-4 equation: 



(3x+2)^2+(3x+2)(x-3)=9x^2-12x-4

We move all terms to the left:

(3x+2)^2+(3x+2)(x-3)-(9x^2-12x-4)=0

We get rid of parentheses

-9x^2+(3x+2)^2+(3x+2)(x-3)+12x+4=0

We multiply parentheses ..

-9x^2+(+3x^2-9x+2x-6)+(3x+2)^2+12x+4=0

We add all the numbers together, and all the variables

-9x^2+(+3x^2-9x+2x-6)+12x+(3x+2)^2+4=0

We get rid of parentheses

-9x^2+3x^2-9x+2x+12x+(3x+2)^2-6+4=0

We add all the numbers together, and all the variables

-6x^2+5x+(3x+2)^2-2=0

We move all terms containing x to the left, all other terms to the right

-6x^2+5x+(3x+2)^2=2

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